Calculate the total pressure in a mixture of 8 g of dioxygen and 4 g of dihydrogen confined in a vessel of 1 `dm^3` at `27^@C`. R=0.083 bar `dm^3K^-1mol^-1`.

Explanation

Number of moles of `H_2=4/2=2.0 mol`
Number of moles of `O_2=8/16=0.5 mol.`
Total number moles of gaseous mixture =2.0 +0.5=2.5 mol.
Ideal gas equation pV-nRT
`p=(nRT)/V`
`=(2.5mol times0.083dm^3K^-1mol^-1 times300K)/(1dm^3)`
=56.025 bar