Calculate the volume occupied by 8.8 g of `CO_2` at `31.1^@C` and 1 bar pressure , R=0.083 bar `LK^-1 mol^-1`.

Explanation

Moles of `CO_2,n=8.8/44=0.2`
R=0.083 bar `LK^-1mol^-1`
T=273+31.1=304.1 K
P=1 Bar
Substituting these values in ideal gas equation
`V=(nRT)/P`
`V=(0.2mol times0.083ba r LK^-1mol^-1times304.1K)/(1 ba r)`
=5.05 lit.