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40 ml of 0.2 M HNO(3) when reacted with ...

40 ml of `0.2 M HNO_(3)` when reacted with 60 ml of `0.3 M NaOH` gave a mixed solution. What is the pH of the resulting solution?

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Since base is more than acid the resultant solution is basic.
`:.[OH^(-)]=((60xx0.3)-(40xx0.2))/100=0.1`
`pOH=-log[1xx10^(-1)]=1`
`pH=14-1=13`
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