A convex lens made up of a material of refractive index `mu_(1)` is immersed in medium of refractive index `mu_(2)` as shown in the figure. The relation between `mu_(1) and mu_(2)` is

Options

A. `mu_(1) lt mu_(2)`
B. `mu_(1) gt mu_(2)`
C. `mu_(1) = mu_(2)`
D. `mu_(1) = sqrt(mu_(2))`

Answer

A

Explanation

Given : Refractive index of material of convex lens `= mu_(1)` and refractive index of medium in which lens is immersed `= mu_(2)` , we know that a convex lens diverages a parallel beam of light when it is placed in a medium of higher placed in a medium of higher refractive index . Since convex lens behaving as diverging lens, therefore `mu_(1) lt mu_(2)` .