A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N . Give the magnitude and direction of the acceleration of the body .

Explanation

Here , m = 5 kg , `bar(a)` = ?
`vec(F_(1))=vec(OA)=8N,vec(F_(2))=vec(OB)=6N`
Resultant force , `vec(F)=vec(OC)=sqrt(F_(1)^(2)+F_(2)^(2))`
`=sqrt(8^(2)+6^(2))=10N`
If `angleAOC=theta,tantheta=(AC)/(OA)=(OB)/(OA)=(6)/(8)=0.75`
`thereforetheta=36^(@)52'`
This is the direction of resultant force and hence the direction of acceleration of the body as shown in figure .

Also,
`a=(F)/(m)=(10)/(5)=2ms^(-2)`