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A stone of mass 0.1 kg is thrown vertica...

A stone of mass 0.1 kg is thrown vertically upwards . Given the magnitude and direction of the net force on the stone (a) during its upward motion (b) during its downward motion (c)at the highest point , where it momentarily comes to rest .

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Mass of stone , m = 0.1 kg.
(a) During upward motion force acts downwards due to acceleration due to gravity .
Magnitude of force ` F = mg = 0.1 xx9.8`
`=0.98N(darr)`
(b) uring downward motion force acts downward . Magnitude of force F = mg
`=0.1xx9.8=0.98N(darr)`
(c) At highest point velocity v = 0 . But still g will act on it only in downward .
Note : In the entire journey of the body force due to gravitational pull acts only in downward direction .
(d) If the body is thrown with an angle of `30^(@)` with horizontal then vertical component of gravitational force does not change , hence in this case
downward force F = mg = `0.1xx98`
= 0.98 newton .
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