The moment of inertia of a flywheel making 300 revolutions per minute is 0.3 `kgm^2` . Find the torque required to bring it to rest in 20s.

Explanation

M.O.I, I = 0.3 kg , time t = 20 sec
` omega_1 = 300 R.P.M = 300/60 = 5 R.P.S., omega_2 =0`
`tau = Ialpha = 0.3 xx (5xx 2pi)/(20) = 0.471 N-m`