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Find the depression of the meniscus in t...

Find the depression of the meniscus in the capillary tube of diameter 0.4 mm dipped in a beaker containing mercury. (Density of mercury =`13.6 times 10^3 kg m^-3` and surface tension of mercury =`0.49 Nm^-1` and angle of contact =`135^@`).

Text Solution

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Diameter of tube=0.4 mm,
`therefore` Radius, `r=0.2mm=0.2/10^3m`
Density of mercury `=13.6 times 10^3 kg //3^3`
Angle of contact, `theta= 135^@`
Surface tension of mercury , `S=0.49 N//m`.
Surface tension , `S=(hrhorg)/(2costheta)`
=` (htimes13.6times10^3times0.2/10^3times9.8)/(2cos135^@)`
`=(htimes13.6times0.2times9.8)/(2cos(180-45)^@)=(-htimes13.6times0.1times9.8)/(2cos45^@)`
`0.49=(-htimes13.6times0.1times9.8)/0.7072`
`thereforeh=(-0.49times0.7072)/(13.6times0.1times9.8)=(-1)/2times0.7072/13.6`ltbrge0.026m.
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