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Two spherical soap bubbles of radii r(1)...

Two spherical soap bubbles of radii `r_(1)` and `r_(2)` in vacuum combine under isothermal conditions. The resulting bubbles has a radius equal to

Text Solution

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When joined is isothermal condition change in temperature of system is zero, So change in internal change of the system is zero.
Let
Surface energy of 1st bubble `U_1= 8 pi R_1^2 S`
Surface energy of 2nd bubble `U_2=8 pi R_2^2 S`
Surface energy of new bubble `U=8 pi R^2 S`
But `8piR^2S=8piR_1^2S+8piR_2^2S`
`implies R^2=R_1^2+R_2^2`
Radius of new bubble R `=sqrt(R_1^2+R_2^2)`
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