Home
Class 11
PHYSICS
The displacement x (in metre ) of a part...

The displacement x (in metre ) of a particle in, simple harmonic motion is related to time t ( in second ) as
` x= 0.01 cos (pi t + pi /4)`
the frequency of the motion will be

A

0.5 Hz

B

1.0 Hz

C

`pi/2 Hz`

D

`pi Hz`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    ERRORLESS |Exercise simple pendulum|61 Videos
  • SIMPLE HARMONIC MOTION

    ERRORLESS |Exercise spring pendulum|55 Videos
  • SIMPLE HARMONIC MOTION

    ERRORLESS |Exercise Energy of simple Harmonic motion|34 Videos
  • ROTATIONAL MOTION

    ERRORLESS |Exercise Practice Problems (Problems based on motion of connected mass)|10 Videos
  • SURFACE TENSION

    ERRORLESS |Exercise Exercise|214 Videos

Similar Questions

Explore conceptually related problems

The displacement x(in metres) of a particle performing simple harmonic motion is related to time t(in seconds) as x=0.05cos(4pit+(pi)/4) .the frequency of the motion will be

The phase (at a time t) of a particle in simple harmonic motion tells

The displacement of a particle in simple harmonic motion in one time period is

The phase of a particle executing simple harmonic motion is pi/2 when it has

The displacement x is in centimeter of an oscillating particle varies with time t in seconds as x = 2 cos [0.05pi t+(pi//3)] . Then the magnitude of the maximum acceleration of the particle will be

A simple harmonic motion is represented by : y = 5(sin 3pi t + sqrt(3) cos 3pi t)cm The amplitude and time period of the motion are :

A particle executes simple harmonic motion and is located at x = a , b and c at times t_(0),2t_(0) and3t_(0) respectively. The frequency of the oscillation is :

A simple harmonic motion is represented by x(t) = sin^(2)omega t - 2 cos^(2) omega t . The angular frequency of oscillation is given by

A simple harmonic motion is represented as x = 20 sin (2pi)t + 0.5]m find amplitude, angular frequency time period and initial phase.

ERRORLESS -SIMPLE HARMONIC MOTION-Time period and frequency
  1. A particle moves such that its acceleration a is given by a = -bx , wh...

    Text Solution

    |

  2. The equation of SHM of a particle is (d^2y)/(dt^2)+ky=0, where k is a ...

    Text Solution

    |

  3. A tunnel has been dug through the centre of the earth and a ball is r...

    Text Solution

    |

  4. The maximum speed of a particle executing S.H.M. is 1 m/s and its maxi...

    Text Solution

    |

  5. The motion of a particle executing S.H.M. is given by x= 0.01 sin 100 ...

    Text Solution

    |

  6. The kinetic energy of a particle executing SHM is 16J. When it is in i...

    Text Solution

    |

  7. The acceleration of a particle performing S.H.M. is 12 cm // sec^(2) ...

    Text Solution

    |

  8. To make the frequency double of an oscillator, we have to

    Text Solution

    |

  9. What is constant in S.H.M.

    Text Solution

    |

  10. If a simple harmonic oscillator has got a displacement of 0.02m and ac...

    Text Solution

    |

  11. The equation of a simple harmonic motion is X=0.34 cos (3000t+0.74) wh...

    Text Solution

    |

  12. Mark the wrong statement

    Text Solution

    |

  13. A particle is SHM is discribed by the displacement function x(t) = a c...

    Text Solution

    |

  14. A particle executes SHM in a line 4 cm long. Its velocity when passing...

    Text Solution

    |

  15. The displacement x (in metre ) of a particle in, simple harmonic motio...

    Text Solution

    |

  16. A simple harmonic wave having an amplitude a and time period T is repr...

    Text Solution

    |

  17. A particle executing simple harmonic motion of amplitude 5 cm has maxi...

    Text Solution

    |

  18. The displacement x(in metres) of a particle performing simple harmonic...

    Text Solution

    |