The period of oscillation of a simple pe...

The period of oscillation of a simple pendulum of constant length at earth surface is T. Its period inside a mine is C

Greater than T

Less than T

Equal to T

connot be compared

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

SIMPLE HARMONIC MOTION
ERRORLESS |Exercise spring pendulum|55 Videos
SIMPLE HARMONIC MOTION
ERRORLESS |Exercise Superposition of S.H. M and Resonance|14 Videos
SIMPLE HARMONIC MOTION
ERRORLESS |Exercise Time period and frequency|18 Videos
ROTATIONAL MOTION
ERRORLESS |Exercise Practice Problems (Problems based on motion of connected mass)|10 Videos
SURFACE TENSION
ERRORLESS |Exercise Exercise|214 Videos

Similar Questions

Explore conceptually related problems

The period of oscillation of a simple pendulum of constant length at surface of the earth is T. Its time period inside mine will be

STATEMENT -1 : The time period of osciallation of a simple pendulum of constant length is more at a place inside a mine than on the surface of the earth. and STATEMENT -2 : The frequency of osciallations ofa simple pendulum is more at aplace inside a mine than on the surface of the earth .

Periodic Motion||Oscillation||Simple Pendulum

Show that the period of oscillation of simple pendulum at depth h below earth's surface is inversely proportional to sqrt(R - h) , where R is the radius of earth. Find out the time period of a second pendulum at a depth R//2 from the earth's surface ?

The mass and the diameter of a planet are three times the repective value for the Earth. The period of oscillation of a simple pendulum on the Earth is 2 s. The period of oscillation of the same pendulum on the planet would be:

The time period of a simple pendulum of infinite length is (R=radius of earth).

The time period of oscillations of a simple pendulum is 1 minute. If its length is increased b 44% then its new time period of oscillation will be

If T_(1) and T_(2) are the time-periods of oscillation of a simple pendulum on the surface of earth (of radius R) and at a depth d, the d is equal to

Consider a simple pendulum. The period of oscillation of the simple pendulum depends on its length and acceleration due to gravity. Then the expression for its time period is

ERRORLESS -SIMPLE HARMONIC MOTION-simple pendulum

The period of a simple pendulum is doubled, when
Text Solution
|
The period of oscillation of a simple pendulum of constant length at e...
Text Solution
|
A simple pendulum has a hollow sphere containing mercury suspended by ...
Text Solution
|
A simple pendulum suspended from the ceiling of a trans has a time per...
Text Solution
|
The mass and diameter of a planet are twice those of earth. What will ...
Text Solution
|
A simple pendulum is set up in a trolley which moves to the right with...
Text Solution
|
Which of the following statements is not true ? In the case of a simpl...
Text Solution
|
The time period of a second’s pendulum is 2 sec. The spherical bob whi...
Text Solution
|
A man measures the period of a simple pendulum inside a stationary lif...
Text Solution
|
A simple pendulum is suspended from the roof of a trolley which moves ...
Text Solution
|
A second's pendulum is placed in a space laboratory orbiting around th...
Text Solution
|
The bob of a simple pendulum of mass m and total energy E will have ma...
Text Solution
|
The length of a second’s pendulum at the surface of earth is 1 m. The ...
Text Solution
|
If the length of a seconds pendulum is increased by 2% then in a day t...
Text Solution
|
The period of simple pendulum is measured as T in a stationary lift. I...
Text Solution
|
The length of a simple pendulum is increased by 1%. Its time period wi...
Text Solution
|
A simple pendulum with a bob of mass ‘m’ oscillates from A to C and ba...
Text Solution
|
idenigu correcy statement among the following
Text Solution
|
The bob of a pendulum of length l is pulled aside from its equilibrium...
Text Solution
|
A simple pendulum executing S.H.M. is falling freely along with the su...
Text Solution
|