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The time period of a simple pendulum of ...

The time period of a simple pendulum of length L as measured in an elevator descending with acceleration g / 3 is

A

`2 pi sqrt((3L)/g)`

B

`pi sqrt((3L)/(g)`

C

`2 pi sqrt(((3L)/(2g)))`

D

`2 pi sqrt((2L)/(3g)`

Text Solution

Verified by Experts

The correct Answer is:
C
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