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A conducting rod AC of length 4l is rota...

A conducting rod `AC` of length `4l` is rotate about a point `O` in a uniform magnetic field `vecB` directed into the paper. `AO=l` and `OC=3l`. Then

A

`V_(A) - V_(O) = (B omega l^(2))/(2)`

B

`V_(O) - V_(C) = (7)/(2)Bomega l^(2)`

C

`V_(A) - V_(C) = 4B omega l^(2)`

D

`V_(C) - V_(O) = (9)/(2)Bomega l^(2)`

Text Solution

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The correct Answer is:
C
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