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In the configuration as shown +q charge ...

In the configuration as shown `+q` charge is placed at origin and Q and Q are placed at distance a and `a_(0)` respectively from origin. If net electrostatic force on charge `(+q)` is along negative y-axis and `theta=theta_(2)//2`, then `(Q//Q)` is equal to:

A

`(a_(0)^(2))/(a^(2))`

B

`(pia_(0)^(2))/(a^(2))`

C

`(pia_(0)^(2))/(4sqrt(2)a^(2))`

D

`(pia_(0)^(2))/(6a^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • Charges 4Q, q and Q and placed along x-axis at positions x=0,x=t//2 and x=1 , respectively. Find the value of q so that force on charge Q is zero

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    A
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    C
    `x_1^2/x_2^2`
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  • In the figure, two point charges +q and -q are placed on the x-axis at (+a,0) and (-a,0) respectively. A tiny dipole of dipolem moment (p) is kept at the origin along the y-axis. The torque on the dipole equals

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