A mixture of A and B in the molar ratio 1:2 forms a maximum boiling azeotrope. Identify the incorrect statement, if A is more volatile. [ Molar mass of A=100, Molar mass of B=50]
A
A liquid solution of A and B having mass % of A=50 will have vapours having mass % of A=50.
B
A liquid solution of A and B having mass % of ` Agt 50%` will have vapours having mass % of Agt50%.
C
A mixture of A and B in the molar mass ratio 1:3 can be seperated into azeotopic mixture and pure A
D
A mixture of A and B in the molar ratio 2:3 can be seperated into azeotropic mixture and pure A.
Text Solution
Verified by Experts
The correct Answer is:
C
Topper's Solved these Questions
LIQUID SOLUTIONS
GRB PUBLICATION|Exercise 52|2 Videos
LIQUID SOLUTIONS
GRB PUBLICATION|Exercise 54|2 Videos
LIQUID SOLUTIONS
GRB PUBLICATION|Exercise 35|6 Videos
IONIC EQUILIBRIUM
GRB PUBLICATION|Exercise All Questions|526 Videos
METALLUGY
GRB PUBLICATION|Exercise Subjective type|1 Videos
Similar Questions
Explore conceptually related problems
A mixture of methane and ethane in the molar ratio of x:y has a mean molar mass of 20. what would be the mean molar mass, if the gases are mixed in the molar ratio of y:x?
Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molar mass of A is 49 u . Molar mass of B will be
Relation Between Empirical And A Formula And Molar Mass Of A Volatile Compound