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1 mole of a non-voltile non-dissociative...

1 mole of a non-voltile non-dissociative solid solute is dissolved in `200` moles of water. The solution is taken to a temperature `T_(K)` (lower than freezing point of solution) to cause ice formation. After removal of ice the remaining solution is taken to `373 K` where vapour pressure is observed is to be `740 mm` of `Hg`. Identify the correct options :
Given data : `K_(f) (H_(2)O) = 2K kg mol^(-1)` and normal boiling point of `H_(2)O = 373 K`.

A

`163` moles of ice will be formed.

B

Temperture to which original solution was colled should be `(2000)/(37 xx 18)K`.

C

Freezing point of orignial solution should be `-(10)/(18).^(@)C`.

D

Ralative lowering of vapour pressure of final solution will be `(1)/(201)`.

Text Solution

Verified by Experts

The correct Answer is:
A, C
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