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A conductor of uniform cross-section is carrying a current of 1 ampere. The number of free electrons flowing across the cross section of the conductor per second is

A

`6.25 times 10^18`

B

`6.25 times 10^17`

C

`6.25 times 10^16`

D

`6.025 times 10^23`

Text Solution

Verified by Experts

1 A electric current = the flow of 1 C charge through the cross-sectional area of the conductor in 1second.
`therefore` Number of free electrons flowing per second
`=(1C)/(charg e ofan el ectron)=(1C)/(1.6 times10^-19C)=6.25times10^18`
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