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Two wires are having length , resistivit...

Two wires are having length , resistivity and their radius in the ratio of 1:3 . Resistance of the thinner wire is `10 Omega`, then the resistance of the other wire will be

A

`40 Omega`

B

`20 Omega`

C

`10 Omega`

D

`5 Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
`R=rho1/A=(rhol)/(pir^2)`
`thereforeR_1/R_2=rho_1/rho_.l_1/l_2.(r_2/r_1)^2=1/3times1/3times(3/1)^2=1`
`R_2=R_1=10Omega`
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