At any place on earth's surface having magnetic latitude `lamda` , if the angle of the be `theta` , prove that , `tantheta=2tanlamda`. Assume that , earth behaves as a magnetised sphere .

At a place on earth 's surface where the horizontal and vertical components of earth's magnetic field are equal ,

At any place in the northern hemisphere of earth , the value of the angle of dip

At a place on the surface of earth , the angle of dip is theta , intensity of earth's magnetism is I and the horizontal and vertical components of earth's magnetism are h and h' respectively . Then

At what depth below the surface of the earth will the acceleration due to gravity be one-fourth of its value on the earth's surface ? Assume that the earth is a homogeneous sphere of uniform density of radius R.

Assuming that the geomagnetic field is developed due to a bar magnet situated at the centre of the earth , prove that , at the magnetic poles , the geomagnetic field is twice that at the magnetic equator .

At any place the horizontal component of earth is sqrt3 times the vertical one. What is the angle of dip at that place?—

Angle of dip at a place = theta , if the angle of dip in a vertical plane making angle delta with the magnetic meridian be theta' , show that , tantheta':tan theta=secdelta:1

The vertical component of earth's magnetic field at a place is sqrt(3) Times of the horizontal component. What is the angle of dip at this place ?

A short bar magnet of magnetic moment 5.25xx10^(-2)J.T^(-1) is placed with its axis perpendicular to the earth's magnetic field . At what distance from the centre of the magnet , the magnet , the resultant field is inclined at 45^(@) with the earth's field on its axis Ignore the length of the magnet in comparison to the distance involved .