A copper wire of length L metre is bent to form a circular loop . If I ampere current flows through the loop , Find out the magnitude of magnetic moment of the loop , .

Answer

2

Explanation

The length of a copper wir = l , let the radius be r when the wire is bent to form a circular coil .
`therefore" " 2pir=l " or, " r =(l)/(2pi)`
`therefore` Area of the circular coil ,
`A=pir^(2)=pixx(l^(2))/(4pi^(2))=(l^(2))/(4pi)`
`therefore` Magnetic moment of the circular wire = `iA=(il^(2))/(4pi)`