Initial charges (with proper sign) on th...

Initial charges (with proper sign) on the plates of two identical capacitors, each of `1muF`, are as shown. When both `S_(1)` and `S_(2)` are closed, the potential difference between `A` and `B` will finally.become :

`2V`

`4V`

`6V`

`0V`

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

CAPACITANCE
PHYSICS GALAXY - ASHISH ARORA|Exercise ADVANCE MCQS|26 Videos
CAPACITANCE
PHYSICS GALAXY - ASHISH ARORA|Exercise UNSOLVED NUMERICAL PROBLEMS|40 Videos
CAPACITANCE
PHYSICS GALAXY - ASHISH ARORA|Exercise CONCEPTUAL MCQA|32 Videos
ATOMIC PHYSICS
PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numerical Problems|39 Videos
CURRENT ELECTRICITY
PHYSICS GALAXY - ASHISH ARORA|Exercise All Questions|389 Videos

Similar Questions

Explore conceptually related problems

The ratio of potential differences between 1muF and 5muF capacitors is

An infinite number of identical capacitors each of capacitance 1 muF are connected 1 muF are connected as shown in Fig. Then the equivalent capacitance between A and B is

Two capacitors C_1=1muF and C_2=3muF each are charged to a potential difference of 100V but with opposite polarity as shown in the figure. When the switch S is closed, the new potential difference between the points a and b is

In a parallel plate capacitor of capacitor 1muF two plates are given charges 2muC and 4muC the potential difference between the plates of the capacitor is

A charge of 1 muC is given to one plate of a parailel - plate capacitor of capacitance 0.1muF and a charge of 2 muC is given to the other plate . Find the potential difference developed between the plate .

In the arrangement shown in, When the swithch S is closed, find . the final potential differnce across the 12 muF capacitor.

Five capacitors are connected as shown in the figure. Initially S is opened and all the capacitors are uncharged . When S is closed and steady state is obtained. Then find out potential difference between the points A and B in volt.

A capacitor of capacitance 500muF is charged at the rate of 100muC//s . The time in which the potential difference will become 20V, is :

PHYSICS GALAXY - ASHISH ARORA-CAPACITANCE-NUMERICAL MCQS

Two capacitors 3muF and 6muF are connected in series across a potentia...
Text Solution
|
Initial charges (with proper sign) on the plates of two identical capa...
Text Solution
|
Three capacitors are connected to D.C source of 100 volts shown in the...
Text Solution
|
In the circuit shown in figure, the final voltage drop across the capa...
Text Solution
|
The plates of a parallel plate capacitor are charged up to 100 v. Now,...
Text Solution
|
A capacitor is charged until its stored energy is 3J and then the char...
Text Solution
|
Four capacitors of capacitance 10muF and a battery of 200V are arrange...
Text Solution
|
A capacitor of capacitance of 2muF is charged to a potential differenc...
Text Solution
|
The equivalent capacitance between terminals A and B in the circuit sh...
Text Solution
|
Two capacitor C(1) and C(2), charged with chargesq(1) and q(2) then th...
Text Solution
|
The two capacitors in the circuit shown in figure are initially unchar...
Text Solution
|
A capacitor stores 50mu c charge when connected across a battery . Whe...
Text Solution
|
Initially two capacitors are charged to different potential difference...
Text Solution
|
The two spherical shells are at large separation, one of them has radi...
Text Solution
|
In the circuit shown in figure, charge on 10 muF capacitor is given as
Text Solution
|
A capacitor consists of two parallel metal plates of area A separated ...
Text Solution
|
The circuit was in the shown state from a long time. Now the switch S ...
Text Solution
|
Four capacitors and two batteries are connected as shown in the figure...
Text Solution
|
Two capacitors are made in series by two metal plates and one I struct...
Text Solution
|
A 3muF and a 5muF capacitor are connected in series across a 30V batte...
Text Solution
|