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A travelling wave y=Asin(kx-omegat+theta...

A travelling wave `y=Asin(kx-omegat+theta)` passes from a heavier string to a lighter string. The reflected wave has amplitude `0.5A`. The junction of the string is at `x=0` The equation of the reflected is :

A

`y'=0.5A sin (kx+omegat+theta)`

B

`y'=-0.5A sin (kx+omegat+theta)`

C

`y'=-0.5A sin (omegat=kx-theta)`

D

`y'=-0.5A sin (kx+omegat-theta)`

Text Solution

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The correct Answer is:
D
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