`1` meter long metallic wire is broken into two unequal parts `P and Q. P` part of the wire in uniformly extended into another wire `R`. Length of `R` is twice the length of `P` and the resistance of `R` is equal to that of `Q`. Find the ratio of the resistance `P` and `R` and also the ratio of the length `P and Q`

One metre long metallic wire is broken into two unequal parts P and Q. The part P is uniformly extended into another wire R. Find the ratio of the resistances of P and R and also the ratio of the lengths P and Q.

In comparing the resistance of two cells P and Q with a sides wire bridge, a balance point is obtained when the sliding contact is 30 cm from the zero end of the wire. The resistances P and Q are interchanged and the balance is obtained at 120 cm from the same emf. Find the ratio of the resistance P and Q and the length of the bridge wire

P,Q and R are three partners in a business. If Ps capital is equal to twice the capital of Q and Qs capital in three times the capital of R, find the ratio of the capitals of P,Q and R.

A given piece of wire of length l and radius r and resistance R is stretched uniformly to wire of radius (r)/(2) .Its new resistance is:

{(p wedge (p to q)) wedge (q to r)} to r is equal to

With resistances P and Q in the left and right gaps of a metre bridge respectively, the null point divides the wire in the ratio 1 : 2 . If P and Q are increased by 20 Omega each, the null point divides the wire in the ratio 3 : 4, then the resistances P and Q are given as :

A wire made of material A has resistance R_1 another wire made of material B having P time the length and q times the radius of first wire has resistance R_2 . If resistivity of B is r times that of A, then calculate R_2//R_1 .