Two cells of EMF 1.5V and 2.0V and internal resistances `2Omega` and `1Omega respevitvely, have their negative terminals joined by a wire of `6Omega` and positive terminals by another `4Omega`. A third resistance of `8Omega` is connected to the midpoints of these two wires. find the potential difference at the ends of the thrid wire

Two cells of emfs 1.5 V and 2.0V internal resistance 2 Omega and 1 Omega respectively have their negative terminals joined by a wire of 6 Omega and positive terminals by another wire of 4 Omega . A third wire of 8 Omega connects the mid points of these two wires. Find the current through 8 Omega and the potential difference at the ends of the third wire.

Two batteries of emfs 2 V and 1 V of internal resistances 1Omega and 2Omega respectively are connected in parallel. The effective emf of the combination is

A potentiometer consists of a wire of length 4 m and resistance 10 Omega . If is connected of cell of emf 2V . The potential difference per unit length of the wire will be

The emf of a battery is 6 V and its internal resistance is 0.6 Omega . A wire of resistance 2.4 Omega is connected to the two ends of the battery, calculate (a) current in the circuit and (b) the potential difference between the two terminals of the battery in closed circuit.

A cell of emf 2 volt and internal resistance 1.5 Omega is connected to the ends of 1 m long wire. The resistance of wire is 0.5 Omega/m . Find the value of potential gradient on the wire.

A 10 m long potentiometery wire has a resistance of 20 Omega it is connected to a battery of emf 6 V and internal resistance 4 Omega find the potential gradient along the wire.

Two cells of e.m.f. 2.5 V and 2.0 V having internal resistance of 1Omega and 2Omega respectively are connected in parallel with similar poles connected together so as to send the current in the same direction through an external resistance of 2Omega . The current in the external resistance is