In the `R_(1) = 10 Omega ,R_(2) = 20 Omega, R_(3) = 40 Omega R_(4) = 80 Omega` and `V_(A) = 5V,V_(B) = 10V,V_(c) = 20V,V_(D) = 15V` The current in the resistance `R_(1)` will be

In the circuit R_(1) = 4 Omega , R_(2) = R_(3) = 15 Omega R_(4) = 30 Omega and E = 10 V Calculate the equivalent resistance of the circuit and current in each resistor

In the circuit shown in Fig, the sources have emf's xi_(1) = 1.5 V, xi_(2) = 2.0 V, xi_(3) = 2.5 V , and the resistances are equal to R_(1) = 10 Omega, R_(2) = 20 Omega, R_(3) = 30 Omega . The internal resistances of the sources are negligible. Find : ltbrtgt (a) the current flowing thorugh teh resistance R_(1) , (b) a potential differences varphi_(A) - varphi_(B) between the points A and B between the points A and B .

In the circuit shown below E_(1) = 4.0 V, R_(1) = 2 Omega, E_(2) = 6.0 V, R_(2) = 4 Omega and R_(3) = 2 Omega . The current I_(1) is

In R_1 = 10 Omega, R_2 = 40 Omega and R_3 = 30 Omega, R_4 = 20 Omega, R_5 = 60 Omega and a 12 V battery is connected to the arrangement, calculate. (a) the total resistance and (b) the total current flowing in the circuit. .

Figure 27-11a shows a multiloop circuit containing one ideal battery and four resistances with the following values: R_(1)=20 Omega, R_(2)=20 Omega, epsi=12V , R_(3)=30 Omega, R_(4)=8.0 Omega (a) What is the current through the battery? (b) What is the current i_(2) through R_(2)? (c) What is the current i_3" through "R_3?

Find the current flowing through the resistance R_(1) of the circuit shown in Fig. If the resistances are equal to R_(1) = 10 Omega. R_(2) = 20 Omega and R_(3) = 30 Omega , and the potential of points 1,2 and 3 are equal to varphi_(1) = 10 V, varphi_(2) = 6V , and varphi_(3) = 5 V

In the given circuit, R_(1) = 10Omega R_(2) = 6Omega and E = 10V, then correct statement is

If in Fig. 12.12, R_(1)=10Omega, R_(2)=40Omega, R_(3)=30Omega, R_(5)=60Omega, and a 12 V battery is connected to the arrangemtn. Calculate (a) the total resistance in the circuit, and (b) the total current flowing in the circuit.

In the circuit shown, E_(1)= 7 V, E_(2) = 7 V, R_(1) = R_(2) = 1Omega and R_(3) = 3 Omega respectively. The current through the resistance R_(3)