In the circuit shownin figure `V_1` and `V_2` are two voltmeter of resistances `3000 Omega` and ` 2000 Omega` respectively. In additions `R_1=2000Omega`, `R_2=3000omega` and `E=200 V` then
a. Fid the reading of voltmeters `V_1` and `V_2` when
i. switch `S` is open
ii. Switch `S` is closed
b. Current through `S`, when it is closed (Disregard the resistance of battery)

In the circuit shown in figure-3.391, V_(1) and V_(2) are two voltmeters having resistances 6000 Omega and 4000 Omega respectively EMF of battery is 250V, having negligible internal resistance. Two resistances R_(1) and R_(2) are 4000 Omega and 6000 Omega respectively. Find the reading of the voltamter V_(1) and V_(2) when (a) Switch S is open ltbgt (b) Switch S is closed

In the circuit shown in figure ammeter and voltmeter are ideal. If E=4 V,R=9Omega and r=1Omega then readings of ammeter and voltmeter are

In the ciruit the cells E_1 and E_2 have emfs of 4V and 8V and internal resistance 0.5 Omega and 1.0 Omega, respectively. Calculate the current through 6 Omega resistance. ltBrgt

A voltmeter has resistance 2000 Omega and range 0.5 V. For increasing its range upto 20V, a resistance of

In the circuit shown, R=2 Omega and V = 20 volt. With switch S open the reading of ammeter is half its reading when ‘S’ is closed. Calculate the resistance of the ammeter.

In the circuit shown, E_(1)= 7 V, E_(2) = 7 V, R_(1) = R_(2) = 1Omega and R_(3) = 3 Omega respectively. The current through the resistance R_(3)

A galvanometer of resistance (G) 10 Omega and a series resistance 250 Omega is used to convert it into a voltmeter of 2 V reading. The current passing through the voltmeter is nearly