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The drift velocity of free electrons in ...

The drift velocity of free electrons in a conductor is `v`, when a current `i` is flowing in it, If both the radius and current are doubled, then the drift velocity will be :

A

` v`

B

`v/2`

C

`v/4`

D

`v/8`

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The correct Answer is:
To solve the problem, we need to analyze how the drift velocity of free electrons in a conductor changes when both the radius and the current are doubled. ### Step-by-Step Solution: 1. **Understand the Formula for Drift Velocity**: The drift velocity \( v_d \) of free electrons in a conductor can be expressed as: \[ v_d = \frac{I}{n \cdot A \cdot e} \] where: - \( I \) is the current, - \( n \) is the number of charge carriers per unit volume, - \( A \) is the cross-sectional area of the conductor, - \( e \) is the charge of an electron. 2. **Express the Cross-Sectional Area**: The cross-sectional area \( A \) of a cylindrical conductor is given by: \[ A = \pi r^2 \] where \( r \) is the radius of the conductor. 3. **Initial Conditions**: Let the initial current be \( I \) and the radius be \( r \). Therefore, the initial area \( A \) can be expressed as: \[ A = \pi r^2 \] 4. **New Conditions**: If both the current and the radius are doubled, the new current \( I' \) and new radius \( r' \) are: \[ I' = 2I \quad \text{and} \quad r' = 2r \] The new area \( A' \) becomes: \[ A' = \pi (r')^2 = \pi (2r)^2 = \pi \cdot 4r^2 = 4\pi r^2 \] 5. **Calculate the New Drift Velocity**: The new drift velocity \( v_d' \) can now be calculated using the new current and area: \[ v_d' = \frac{I'}{n \cdot A'} = \frac{2I}{n \cdot 4\pi r^2} \] 6. **Relate New Drift Velocity to Initial Drift Velocity**: We can express the new drift velocity in terms of the original drift velocity: \[ v_d' = \frac{2I}{4(n \cdot \pi r^2)} = \frac{1}{2} \cdot \frac{I}{n \cdot \pi r^2} = \frac{1}{2} v_d \] 7. **Conclusion**: Therefore, when both the radius and the current are doubled, the new drift velocity \( v_d' \) is: \[ v_d' = \frac{v_d}{2} \] Thus, the drift velocity will be half of the original drift velocity. ### Final Answer: The drift velocity will be \( \frac{v}{2} \).
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