Ten cells each of emf `1 V` and internal resistance `1Omega` are connected inseries. In this arrangement, polarity of two cells is reversed and the system is connected to an external resistance of `2Omega`. Find the current in the circuit.

Two cells of emf 1.25V,0.75V and each of internal resistance 1Omega are connected in parallel. The effective emf will be

4 cells each of emf 2 V and internal resistance of 1Omega are connected in parallel to a load resistor of 2Omega . Then the current through the load resistor is

Three identical cells, each of emf 2 V and internal resistance 0.2Omega are connected in series to an external resistor of 7.4Omega . Calculate the current in the circuit.

Three identical cells of emf 2 V and internal resistances 0.20 Omega are connected in series. The combination is further connected to an external resistor of 6 Omega . Calculate the current through 6 Omega resistor.

There are n cells, each of emf E and internal resistance r, connected in series with an external resistance R. One of the cells is wrongly connected, so that it sends current in the opposite direction. The current flowing in the circuit is

Four cell each of emf 2 V and internal resistance 1 ohm are connected n parallel with an external resistance of 6 ohm. The current in the external resistance is

Four cells, each of emf E and internal resistance r, are connected in series across an external resistance reverse. Then, the current in the external circuit is

Two cells of 1.5 V and 2 V , having internal resistances of 1Omega and 2Omega respectively, are connected in parallel so as to read the current in the same direction through an external resistance of 5 Omega . The current in the external resistance will be