In Figure `E_1=12V` and `E_2=8V`
(a) What is the direction of the current in the resistor?
(b) Which battery is doing positive work?
(c) Which point, `A` or `B`, is at the higher potential?

In the circuit shown in figure, E = 120 V, R_1 = 30.0Omega, R_2 = 50.0 Omega and L=0.200H . Switch S is closed at t = 0 . Just after the switch is closed. (a) What is the potential difference V_(ab) across the inductor R_1 ? (b) Which point, a or b , is at higher potential? (c) What is the potential difference V_(cd) across the inductor L ? (d) Which point, c or d , is at a higher potential? The switch is left closed for a long time and then is opened. Just after the switch is opened (e) What is the potential difference V_(ab) across the resistor R_1 ? (f) Which point a or b, is at a higher potential? (g) What is the potential difference V_(cd) across the inductor L ? (h) Which point, c or d , is at a higher potential?

An ideal voltmeter V is connected to a 2.0 Omega resistor and a battery with emf 5.0 V and internal resistance 0.5 Omega as shown in figure (a) What is the current in the 2.0 Omega resistor? (b) What is the terminal voltage of the battery? (c) What is the reading of the voltmeter?

In figure i_(1) = 10 e^(-2t) A, i_(2) = 4 A, v_(C ) = 3 e^(-2t) V The current i_(L) is

Five capacitors are connected in series as shown in figure with a battery of emf 20V and the point B is earthed. The potential of point A is

In the circuit given in the figure, both batteries are ideal . Emf E_1 of battery 1 has a fixed value, but emf E_2 of battery 2 can be varied between 1.0V and 10.0 V . The graph gives the currents through the two batteries as a function of E_2 but are not marked as which plot corresponds to which battery. But for both plots, current is assumed to be negative when the direction of the current through the battery is opposite to the direction of that battery's emf (direction of emf is from negative to positive.) The value of emf E_1 is

In the circuit given in the figure, both batteries are ideal . Emf E_1 of battery 1 has a fixed value, but emf E_2 of battery 2 can be varied between 1.0V and 10.0 V . The graph gives the currents through the two batteries as a function of E_2 but are not marked as which plot corresponds to which battery. But for both plots, current is assumed to be negative when the direction of the current through the battery is opposite to the direction of that battery's emf (direction of emf is from negative to positive.) , The resistance R_2 is equal to

Four identical capacitors are connected in series with a 10 V battery as shown in the figure. The point N is earthed. The potentials of points A and B are