Resistances `R_(1) and R_(2)`, each `600 Omega`, are connected in series as shown in figure-3.382. The potential difference between points A and B is 120 V. Find the reading of voltmeter connected between points C and D ifits resistance is `120 Omega`

Resistances R_(1) and R_(2) each 60 are connected in series as shown in figure. The potential difference between A and B is kept 120 volt. Then what will be tha reading of voltmeter connected between thapoint C and D if resistance of voltmeter is 120 Omega ?

In the circuit shown in figure potential difference between point A and B is 16 V . Find the current passing through 2 Omega resistance.

Five resistance, each of 5Omega are connected as shown in figure. Find the equivalent resistance between points (1) A and B , (2) A and C .

Eight resistances each of resistance 5 Omega are connected in the circuit as shown in figure. The equivalent resistance between A and B is

Resistance R_1 and R_2 , each 60 Omega , are connected in series. The points A and B is 120 V . Find the reading of voltmeter connected resistance r=120Omega

Twelve resistances each of resistance R are connected in the circuit as shown in fig. Net resistance between points A and C would be

Twelve resistors each of resistance 1 Omega are connected in the circuit shown in figure. Net resistance between point A and H would be

Five resistors, each 3 Omega , are connected as shown in (fig. 3.23). Calculate the resistance between the points (a) A and b between the point C and D . .

Two resistances R_(1) = 100 +- 3 Omega and R_(2) = 200 +- 4 Omega are connected in series . Find the equivalent resistance of the series combination.