The switch `S` is closed at `t=0` . the capacitor `C` is uncharged but `C_0` has a charge `Q_0=2muC` at `t=0`. If `=100Ommega` , `C=2muF` , `C_0=2muF,E=4V`. Calculate i (`t`) in the circuit.

The switch S is closed aty t = 0. the capacitor C is uncharged but C_0 has a charge q_0 at t =0. Calculate the current i(t) in the circuit

In the circuit shown key is closed at t=0 with capacitor initially uncharged.

Switch is closed at t = 0 then the current in the circuit at t = L/2R is

In the circuit shown, the switch 'S' is closed at t =0 . Then capacitor is initially uncharged. Then the current through the resistor R = 8Omega at t = 0.4 xx 10^(-3) sec is (Take e^(-2) = 0.135 )

For the arrangement shown in the figure, the switch is closed at t = 0 . C_2 is initially uncharged while C_1 has a charge of 2muC (a) Find the current comingn out of the battery just after the switch is closed. (b) Find the charge on the capacitors in the steady state condition.

In the given circuit switch is closed at t = 0 . The charge flown in time t = T_c (where T_c is time constant).

Consider the situation shown in figure.The switch is closed at t=0 when the capacitor C_(1) as a function of time t .

The switch S of the circuit is closed at t = 0. Find the current (in Amp.) through the capacitor when the switch S is closed at t = 0