A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of `12.5%` by mass `2.8g` of the mineral on heating lost `1.32g` of `CO_2`. What is the % by mass of the other metal ?

A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 12.5% by mass.2.8 g of the mineral on heating loat 1.32g of CO_(2) . What is the % by mass of the other metal ?

A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 15.0% by weight, 3.0 g of the mineral on heating lost 1.10 g of CO_(2) . The percent by weight of other metal is

A mixture contains equi-molar quantities of carbonates of two bivalent metals. One metal is present the extent of 13.5% by weight in the mixture and 2.50 g of the mixture on heating leaves a residue of 1.18 g . Calculate the percentage by weight of the other metal.

1.00 g of a mixture, consisting of equal number of moles of carbonates of two alkali metals, required 44.4 " mL of " 0.5 N-HCl for complete reaction. If the atomic weight of one of the metal is 7.00. Find the atomic weight of the other metal. What will be the total amount of sulphate formed on quantitative conversion of 1.00 g of the mixture into sulphates?