Home
Class 11
PHYSICS
The potential energy (U) of a body of u...

The potential energy (U) of a body of unit mass moving in a one-dimension foroce field is given by
`U=(x^(2)-4x+3)` . All untis are in S.L

A

Find the equilibrium position of the body

B

Show that oscilliations of the body about this equilibrium positon in sample harmonic motion and find its time period

C

Find the amplitude of oscilliations if speed of the body at equilibrium position is `2sqrt6 m//s`

D

Find the amplitude of oscillators if speed of the body at equlibrium position is `2sqrt(6) m//s`.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
Promotional Banner

Topper's Solved these Questions

  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS|Exercise Multiple Correct Answer Type|6 Videos
  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS|Exercise Subjective type|3 Videos
  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS|Exercise Integer|10 Videos
  • KINETIC THEORY OF GASES AND FIRST LAW OF THERMODYNAMICS

    CENGAGE PHYSICS|Exercise Interger|11 Videos
  • MISCELLANEOUS KINEMATICS

    CENGAGE PHYSICS|Exercise Interger type|3 Videos

Similar Questions

Explore conceptually related problems

The potential energy U of a body of unit mass moving in one dimensional conservative force field is given by U=x^2-4x+3 . All units are is SI. For this situation mark out the correct statement (s).

Potential energy (U) of a body of unit mass moving in a one-dimension conservative force fileld is given by, U = (x^(2) – 4x + 3). All units are in S.I. (i) Find the equilibrium position of the body. (ii) Show that oscillations of the body about this equilibrium position is simple harmonic motion & find its timeperiod. (iii) Find the amplitude of oscillations if speed of the body at equilibrium position is 2 sqrt(6) m/s.

The potential energy of an object of mass m moving in xy plane in a conservative field is given by U = ax + by , where x and y are position coordinates of the object. Find magnitude of its acceleration :-

The potential energy of a particle of mass 1 kg in a conservative field is given as U=(3x^(2)y^(2)+6x) J, where x and y are measured in meter. Initially particle is at (1,1) & at rest then:

The potential energy of a body mass m is U=ax+by the magnitude of acceleration of the body will be-

The potential energy of body of mass 2 kg moving along the x-axis is given by U = 4x^2 , where x is in metre. Then the time period of body (in second) is

The potential energy of a particle of mass 2 kg moving along the x-axis is given by U(x) = 4x^2 - 2x^3 ( where U is in joules and x is in meters). The kinetic energy of the particle is maximum at

The potential energy of a particle of mass 1 kg moving along x-axis given by U(x)=[(x^(2))/(2)-x]J . If total mechanical speed (in m/s):-