The refracting angle of a glass prism is `30^@.` A ray is incident onto one of the faces perpendicular to it. Find the angle `delta` between the incident ray and the ray that leaves the prism. The refractive index of glass is `mu=1.5.`

The cross section of a glass prism mu=2 has the form of an isosceles right-angled triangle. It is submerged in a liquid of refractive index 1.2 . A ray is incident on to one of the equal faces perpendicularly. What is the angle between the direction of incident ray and the ray that emerges from the prism ?

An equilateral triangular prism is made of glass (mu = 1.5) . A ray of light is incident normally on one of the faces. The angle between the incident and emergent ray is

Light is incident on a glass surface at polarising angle of 57.5^(@) Then the angle between the incident ray and the refracted ray is

The angle of a prism is 30^(@) . The rays incident at 60^(@) on one refracting face suffer a deviation of 30^(@) . Then the angle of emergence is :

The refracting angle of a glass prism is 60^@ and mu of its material is 1.45 . Calculate angle of incidence at the first that will just reflect internaly the ray at the second face.

A light ray is travelling from air to glass. True reflected and refracted rays are perpendicular to each other. If the angle of incidence in air is I the refractive index of glass is

A ray of light is incident at 60^(@) on one face of a prism of angle 30^(@) and the emergent ray makes 30^(@) with the incident ray. The refractive index of the prism is

A ray of light is incident at 65^(@) on one face of a prism of angle of 30^(@) and the emergent ray makes 35^(@) with the incident ray. The refractive index of the prism is: