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if (1-costheta)/(sintheta)=(sqrt(3))/(3)...

if `(1-costheta)/(sintheta)=(sqrt(3))/(3)`, then `theta`=

A

`15^(@)`

B

`30^(@)`

C

`45^(@)`

D

`60^(@)`

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The correct Answer is:
To solve the equation \(\frac{1 - \cos \theta}{\sin \theta} = \frac{\sqrt{3}}{3}\), we will follow these steps: ### Step 1: Rewrite the equation Start with the given equation: \[ \frac{1 - \cos \theta}{\sin \theta} = \frac{\sqrt{3}}{3} \] ### Step 2: Cross-multiply Cross-multiply to eliminate the fraction: \[ 1 - \cos \theta = \frac{\sqrt{3}}{3} \sin \theta \] ### Step 3: Rearrange the equation Rearranging gives: \[ 1 - \cos \theta = \frac{\sqrt{3}}{3} \sin \theta \] ### Step 4: Isolate the trigonometric terms We can express this as: \[ \frac{1}{\sin \theta} - \frac{\cos \theta}{\sin \theta} = \frac{1}{\sqrt{3}} \] This can be rewritten using cosecant and cotangent: \[ \csc \theta - \cot \theta = \frac{1}{\sqrt{3}} \] ### Step 5: Use trigonometric identities Using the identity \(\csc \theta - \cot \theta = \tan \frac{\theta}{2}\), we can rewrite the equation: \[ \tan \frac{\theta}{2} = \frac{1}{\sqrt{3}} \] ### Step 6: Solve for \(\frac{\theta}{2}\) The value of \(\tan \frac{\theta}{2} = \frac{1}{\sqrt{3}}\) corresponds to an angle of \(30^\circ\): \[ \frac{\theta}{2} = 30^\circ \] ### Step 7: Solve for \(\theta\) Now, multiply both sides by 2 to find \(\theta\): \[ \theta = 60^\circ \] ### Final Answer Thus, the value of \(\theta\) is: \[ \theta = 60^\circ \] ---

To solve the equation \(\frac{1 - \cos \theta}{\sin \theta} = \frac{\sqrt{3}}{3}\), we will follow these steps: ### Step 1: Rewrite the equation Start with the given equation: \[ \frac{1 - \cos \theta}{\sin \theta} = \frac{\sqrt{3}}{3} \] ...
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