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If (secx)(tanx) lt 0, which of the follo...

If `(secx)(tanx) lt 0`, which of the following must be true?
I. tan`xlt0`
II. Csc x cot `x lt 0`
III. X is in the third or fourth quadrant

A

I only

B

II only

C

III only

D

II and III

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To solve the inequality \( \sec x \tan x < 0 \), we can follow these steps: ### Step 1: Rewrite the expression in terms of sine and cosine. We know that: \[ \sec x = \frac{1}{\cos x} \quad \text{and} \quad \tan x = \frac{\sin x}{\cos x} \] Thus, we can rewrite the expression: \[ \sec x \tan x = \frac{1}{\cos x} \cdot \frac{\sin x}{\cos x} = \frac{\sin x}{\cos^2 x} \] ### Step 2: Set up the inequality. We need to solve the inequality: \[ \frac{\sin x}{\cos^2 x} < 0 \] ### Step 3: Analyze the signs of the numerator and denominator. - The term \( \cos^2 x \) is always non-negative (since it is a square). Therefore, the sign of the entire expression \( \frac{\sin x}{\cos^2 x} \) depends solely on the sign of \( \sin x \). - For the expression to be less than zero, \( \sin x \) must be negative: \[ \sin x < 0 \] ### Step 4: Determine the quadrants where \( \sin x < 0 \). The sine function is negative in the third and fourth quadrants. Therefore: - \( x \) lies in the third quadrant (where \( \sin x < 0 \)) or the fourth quadrant (where \( \sin x < 0 \)). ### Step 5: Evaluate the options. Now, let's analyze the given statements: 1. **I. \( \tan x < 0 \)**: This is true in the second and fourth quadrants, but not necessarily in the third quadrant. So, this statement is not always true. 2. **II. \( \csc x \cot x < 0 \)**: This is equivalent to \( \frac{1}{\sin x} \cdot \frac{\cos x}{\sin x} < 0 \) or \( \frac{\cos x}{\sin^2 x} < 0 \). Since \( \sin x < 0 \) and \( \cos x \) can be either positive or negative depending on the quadrant, this statement is not necessarily true. 3. **III. \( x \) is in the third or fourth quadrant**: This is true since we established that \( \sin x < 0 \) holds true in these quadrants. ### Conclusion: The only statement that must be true is: - **III. \( x \) is in the third or fourth quadrant.** ### Final Answer: The correct answer is **III only**. ---

To solve the inequality \( \sec x \tan x < 0 \), we can follow these steps: ### Step 1: Rewrite the expression in terms of sine and cosine. We know that: \[ \sec x = \frac{1}{\cos x} \quad \text{and} \quad \tan x = \frac{\sin x}{\cos x} \] Thus, we can rewrite the expression: ...
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