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In the figure above, angleA=110^(@),a=sq...

In the figure above, `angleA=110^(@),a=sqrt(6), and b=2.` what is the value of `angleC`?

A

`50^(@)`

B

`25^(@)`

C

`20^(@)`

D

`15^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
Law of sines:
`(sin110^(@))/(sqrt(6))=(sinB)/(2),sinB=(2sin110^(@))/(sqrt(6))~~0.7673.Sin^(-1)(0.7673)=angleB=50^(@)`. Therefore,
`angleC=180^(@)-110^(@)-50^(@)=20^(@)`.
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