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Log(a^(2)-b^(2))=...

`Log(a^(2)-b^(2))=`

A

`loga^(2)-logb^(2)`

B

`"log"(a^(2))/(b^(2))`

C

`"log"(a+b)/(a-b)`

D

`log(a+b)+log(a-b)`

Text Solution

Verified by Experts

The correct Answer is:
D
`Log(a^(2)-b^(2))=log(a+b)(a-b)=log(a+b)+log(a-b)`.
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