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p(x)=4(-x^(3)+11x+12)-6(x-c) In the po...

`p(x)=4(-x^(3)+11x+12)-6(x-c)`
In the polynomial function p(x) defined above c is a constant. If p(x) is divisible by x, what is the value of c?

A

`-8`

B

`-6`

C

0

D

6

Text Solution

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The correct Answer is:
To solve the problem, we need to find the value of \( c \) such that the polynomial \( p(x) \) is divisible by \( x \). This means that when we substitute \( x = 0 \) into \( p(x) \), the result should be zero. ### Step-by-Step Solution: 1. **Write down the polynomial**: \[ p(x) = 4(-x^3 + 11x + 12) - 6(x - c) \] 2. **Distribute the terms**: - First, distribute \( 4 \) in the first part: \[ p(x) = 4(-x^3) + 4(11x) + 4(12) - 6(x - c) \] - This simplifies to: \[ p(x) = -4x^3 + 44x + 48 - 6x + 6c \] 3. **Combine like terms**: - Combine the \( x \) terms: \[ p(x) = -4x^3 + (44x - 6x) + 48 + 6c \] - This simplifies to: \[ p(x) = -4x^3 + 38x + 48 + 6c \] 4. **Set \( p(0) = 0 \)**: - Since \( p(x) \) is divisible by \( x \), we need: \[ p(0) = 0 \] - Substitute \( x = 0 \) into \( p(x) \): \[ p(0) = -4(0)^3 + 38(0) + 48 + 6c = 48 + 6c \] - Set this equal to zero: \[ 48 + 6c = 0 \] 5. **Solve for \( c \)**: - Rearranging gives: \[ 6c = -48 \] - Dividing both sides by 6: \[ c = \frac{-48}{6} = -8 \] ### Conclusion: The value of \( c \) is \( -8 \).
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