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If alpha=tan^(-1)((sqrt(3)x)/(2y-x)),bet...

If `alpha=tan^(-1)((sqrt(3)x)/(2y-x)),beta=tan^(-1)((2x-y)/(sqrt(3y)))" then "alpha-beta=`

A

`(pi)/(6)`

B

`(pi)/(3)`

C

`(pi)/(2)`

D

`(-pi)/(3)`

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