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Find a parametric form of vector equation of a plane which is at a distance of 7 units from the origin having3,-4,5 as direction ratios of a normal to it .

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Explore conceptually related problems

Find a parametric form of vector equation of a plane which is at a distance of 7 units from the origin having 3,-4,5 as direction ratios of a normal to it.

Find the vector equation of a plane with is at a distance of 7 units from the origin and normal to the vector 3hati+5hatj-6hatj .

Knowledge Check

  • The vector equation of a plane which is at a distance of 6/sqrt29 from the origin and its normal vector from the origin is 2hati-3hatj+4hatk is

    A
    `vecr.(2hati-3hatj+4hatk)=6/sqrt29`
    B
    `vecr.(2/sqrt29 hati-3/sqrt29 hatj+4/sqrt29hatk)=6/sqrt29`
    C
    both (a) and (b)
    D
    none of these
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    Find the vector and cartesian form of the equation of the plane which is at distance of 6 units from the origin and perpendicular to 2hati+3hatj-6hatk .

    Find the vector equation of the plane which is at a distance of 6/sqrt29 from the origin and its normal vector from the origin is 2hati-3hatj+4hatk . Also find its cartesian form.