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Equation of the straight line perpendicu...

Equation of the straight line perpendicular to the line x-y+5=0, through the point of intersection the y-axis and the given line

A

x-y-5=0

B

x+y-5=0

C

x+y+5=0

D

x+y+10=0

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • Equation of the straight line perpendicular to the linex−y+5 = 0, through the point of intersection the y-axis and the given line

    A
    x − y − 5=0
    B
    x + y − 5=0
    C
    x + y +5=0
    D
    x + y + 10 = 0

  • ax + by - a^(2) = 0 , where a, b non-zero, is the equation to the straight line perpendicular to a line l and passing through the point where I crosses the x-axis. Then equation to the line / is

    A
    `(x)/(b)-(y)/(a)=1`
    B
    `(x)/(a)-(y)/(b)=1`
    C
    `(x)/(b)+(y)/(a)=ab`
    D
    `(x)/(a)-(y)/(b)=ab`

  • The equation of the line perpendicular to the line 2x – 3y + 5 = 0 and making an intercept 3 with y-axis is

    A
    3x + 2y - 6= 0
    B
    3x + 2y – 12 = 0
    C
    3x – 2y - 6= 0
    D
    3x + 2y +6= 0

    • Similar Questions

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    Find the equation of a straight line parallel to Y axis and passing through the point of intersection of the lines 4x+5y=13 and x-8y+9=0 .

    Find the equation of the line perpendicular to the line x/a-y/b=1 and passing through a point at which it cuts the x-axis.

    Find the equation of the straight line passing through the point of intersection of the lines 5x-8y+23=0 and 7x+6y-71=0 and is perpendicular to the line joining the points (5,1) and (-2,2) .

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