A cannon a target are `5.0 km` apart on the same horizontal plane. How long will the shell launched with a velocity of `240 ms^-1` take to reach the tanget ? `(g=10ms^-2)`

A cannon and a target are 5.0 km apart on the same horizontal plane. How long will the shell, launched with a velocity of 240 m s^(-1) , take to reach the target ? (g=10 ms^(-2))

A cannon and a target are 5.10 km apart and located at the same level. How soon will the shell launched with the initial velocity 240 m//s reach the target in the absence of air drag?

What are the angles of projection of a projectile projected with velocity 30 ms^(-1) , so that the horizontal range is 45 m ? Take g = 10 ms^(-2) .

A ball is projected horizontallu from a top of tower with a velocity of 10 ms^(-1) . Find the velocity of the ball after 0.5 s. Take g= 10 ms^(-2) .

A ball is projected from the bottom of an inclined plane of inclination 30^@ , with a velocity of 30 ms^(-1) , at an angle of 30^@ with the inclined plane. If g = 10 ms^(-2) , then the range of the ball on given inclined plane is

A body is projected at an angle of 30^@ with the horizontal and with a speed of 30 ms^-1 . What is the angle with the horizontal after 1.5 s ? (g = 10 ms^-2) .

A particle is projected with initial velocity of hati+2hatj . The eqaution of trajectory is (take g=10ms^(-2))

A jet aeroplane is flying at a constant height of 2 km with a speed 360 kmh^(-1) above the ground towards a target and releases a bomb. After how much time it will hit the target and what will be the horizontal distance of the aeroplane from the target so that the bomb should hit the target ? (Take g = 10 ms^(-2))