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A set of n identical cubical blocks lies...

A set of n identical cubical blocks lies at rest parallel to each other along a line on a smooth horizontal surface. The separation between the near surfaces of any two adjacent blocks is L . The block at one end is given a speed v towards the next one at time 0 t . All collisions are completely inelastic, then

A

The last block starts moving at `t=((n+1)L)/(v)`

B

The last block starts moving at `t=(n(n-1)L)/(2v)`

C

The center of mass of the system will have the final speed v

D

The center of mass of the system will have the final speed `(v)/(n)`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • A set of a identical cubical blocks lies at rest parallel to each other along a line on a smooth horizontal surface. The separation between the near surface of any two adjacent blocks is L . The block at one and is given a speed v towards the next one at time t = 0 . All collisiona are completely inelastic , then the last block starts moving at

    A
    `((n-1)L)/(v)`
    B
    `(n (n-1)L)/(2v)`
    C
    `((n+1)L)/(v)`
    D
    `(n (n+1)L)/(2v)`

  • Two identical 5 kg blocks are moving with same speed of 2 m//s towards each other along a frictionless horizontal surface . The two blocks collide , stick together and come to rest. Consider the two blocks as a system . The work done by the external and ijnternal force are respectively:

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    `0,0`
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  • Two blocks A and B are placed one over the other on a smooth horizontal surface. The maximum horizontal force that can be applied on lower blockB, so that A and B move without separation is 49 N. The coefficient of friction between A and B is

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    B
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