A uniform chain of mass M and length L is held vertically in such a way that its lower end just touches the horizontal floor. The chain is released from rest in this position. Any portion that strikes the floor comes to rest. Assuming that the chain does not form a heap on the floor, calculate the force exerted by it on the floor when a length x has reached the floor.

Options

A. Force exerted by chain on the floor when a length x has reached the floor is `(3Mgx)/(L)`
B. Force exerted by chain on the floor when a length x has reached the floor is `(3Mgx)/(L)`
C. Force exerted on the floor by the falling part of chain at any moment is twice as great as force exerted by the part already resting on the floor.
D. Force exerted on the floor by the falling part of chain at any moment is same as foce exerted by the part already resting on the floor.