A particle of mass `4m` is projected from the ground at some angle with horizontal. Its horizontal range is `R`. At the highest point of its path it breaks into two pieces of masses `m` and `3m`, respectively, such that the smaller mass comes to rest. The larger mass finally falls at a distance `x` from the point of projection, where `x` is equal to

Options

A. `(3R)/(4)`
B. `(3R)/(2)`
C. `(5R)/(4)`
D. 3R

Answer

C