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A sphere strikes a wall and rebounds wit...

A sphere strikes a wall and rebounds with coefficient of restitution `(1)/(3)`. If it rebounds with a velocity of `0.1 m//sec` at an angle of `60^(@)` to the normal to the wall, the loss of kinetic energy is :

A

`50%`

B

`33(1)/(3)%`

C

`40%`

D

`66(2)/(3)%`

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The correct Answer is:
To solve the problem of finding the loss of kinetic energy when a sphere strikes a wall and rebounds, we can follow these steps: ### Step 1: Understand the Given Data - Coefficient of restitution \( e = \frac{1}{3} \) - Final velocity \( V = 0.1 \, \text{m/s} \) - Angle of rebound \( \theta = 60^\circ \) ### Step 2: Break Down the Final Velocity into Components The final velocity can be broken down into its horizontal and vertical components: - Horizontal component: \( V_x = V \cos(60^\circ) = 0.1 \cos(60^\circ) = 0.1 \times \frac{1}{2} = 0.05 \, \text{m/s} \) - Vertical component: \( V_y = V \sin(60^\circ) = 0.1 \sin(60^\circ) = 0.1 \times \frac{\sqrt{3}}{2} = 0.05\sqrt{3} \, \text{m/s} \) ### Step 3: Use the Coefficient of Restitution The coefficient of restitution relates the velocities before and after the collision: \[ e = \frac{V_x}{U_x} \] Where \( U_x \) is the initial horizontal component of the velocity before the collision. Rearranging gives: \[ U_x = \frac{V_x}{e} = \frac{0.05}{\frac{1}{3}} = 0.15 \, \text{m/s} \] ### Step 4: Determine the Initial Vertical Component Since the vertical component does not change during the collision: \[ U_y = V_y = 0.05\sqrt{3} \, \text{m/s} \] ### Step 5: Calculate the Initial Velocity Now, we can find the magnitude of the initial velocity \( U \): \[ U = \sqrt{U_x^2 + U_y^2} = \sqrt{(0.15)^2 + (0.05\sqrt{3})^2} \] Calculating this: \[ U = \sqrt{0.0225 + 0.0075} = \sqrt{0.03} = 0.1732 \, \text{m/s} \] ### Step 6: Calculate the Initial and Final Kinetic Energies The kinetic energy is given by: \[ KE = \frac{1}{2} m v^2 \] - Initial kinetic energy \( KE_i = \frac{1}{2} m U^2 = \frac{1}{2} m (0.1732)^2 \) - Final kinetic energy \( KE_f = \frac{1}{2} m V^2 = \frac{1}{2} m (0.1)^2 \) ### Step 7: Find the Loss of Kinetic Energy The loss of kinetic energy \( \Delta KE \) is given by: \[ \Delta KE = KE_i - KE_f = \frac{1}{2} m (0.1732^2 - 0.1^2) \] Calculating the values: \[ \Delta KE = \frac{1}{2} m (0.03 - 0.01) = \frac{1}{2} m (0.02) = 0.01 m \] ### Conclusion The loss of kinetic energy is \( 0.01 m \) joules, where \( m \) is the mass of the sphere.
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