a quantity `X` is given by `epsilon_(0)L(DeltaV)/(Deltat)` where `in_(0)` is the permittivity of the free space, L is a length, `DeltaV` is a potential difference and `Deltat` is a time interval. The dimensinal formula for `X` is the same as that of
A
resistance
B
charge
C
voltage
D
current
Text Solution
Verified by Experts
The correct Answer is:
D
Topper's Solved these Questions
IIT QUESTIONS 2
D MUKHERJEE|Exercise Assertion -Reason type|2 Videos
IIT QUESTIONS 2
D MUKHERJEE|Exercise Linked -comprehension type|3 Videos
IIT QUESTIONS 1
D MUKHERJEE|Exercise Matrix-Matching Type|1 Videos
IIT QUESTIONS 3
D MUKHERJEE|Exercise Matrix matching type|1 Videos
Similar Questions
Explore conceptually related problems
A quantity X is given by in_(0) L(DeltaV)/(Delta t) , where in_(0) is the permittivity of free space, L is a length, DeltaV is a potential difference and Delta t is a time interval. The dimensional formula for X is the same as that of -
A quantity X is given by epsilon_(0) L(DeltaV)/(Deltat) , where epsilon_(0) is the permittivity of free space L is a length DeltaV is a potnetial difference and Delta is a time internval. The dimensional forumla to X is the same as that of
A quantity X is given by epsilon_(p) L(delta V)/(delta t) , where epsilon_(p) is the permitivity of free space ,L is a length , delta V is a potential diffrence and deltat is a time interval . The dimensional formula for X is the seme as that of
(a) In the formula X=3YZ^(2) , X and Z have dimensions of capcitnce and magnetic inlduction, respectively. What are the dimensions of Y in MKSQ system? (b) A qunatity X is given by epsilon_(0) L ((Delta)V)/((Delta)r) , where epsilon_(0) is the permittivity of free space, L is a lenght, DeltaV is a potential difference and Deltat is a time interval. Find the dimensions of X . (c) If E,M,J and G denote energy , mass , angular momentum and gravitational constant, respectively. find dimensons of (E J^(2))/(M^(5) G^(2)) (d) If e,h,c and epsilon_(0) are electronic charge, Planck 's constant speed of light and permittivity of free space. Find the dimensions of (e^(2))/(2epsilon_(0)hc) .
A quantity y is given by y=epsilon_0L(dV)/dt , where epsilon_0 is the permittivity of free space, L is length, dV is small potential difference and dt is small time interval. The dimensional formula for y is same as that of
The quantity X = (epsilon_(0)LV)/(t) where epsilon_(0) is the permittivity of free space, L is length, V is the potential difference and t is time. The dimensions of X are the same as that of