The ends of a stretched wire of length `L` are fixed at `x = 0 and x = L`. In one experiment, the displacement of the wire is `y_(1) = A sin(pi//L) sin omegat` and energy is `E_(1)` and in another experiment its displacement is `y_(2) = A sin (2pix//L ) sin 2omegat` and energy is `E_(2)`. Then
A
`E_(2)=E_(1)`
B
`E_(2)=2E_(1)`
C
`E_(2)=4E_(1)`
D
`E_(2)=16E_(1)`
Text Solution
Verified by Experts
The correct Answer is:
C
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