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Given that E(Fe^(2+)//Fe)^(.)=-0.44V,E(...

Given that `E_(Fe^(2+)//Fe)^(.)=-0.44V,E_(Fe^(3+)//Fe^(2+))^(@)=0.77V` if `Fe^(2+),Fe^(3+)` and `Fe` solid are kept together then

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Standard electrode potentials are Fe^(2+)//Fe, E^(@) = -0.44 V Fe^(3+)//Fe^(2+), E^(@) = -0.77 V If Fe^(3+), Fe^(2+) , and Fe block are kept together, then

If E_(Fe^(2+)//Fe)^(@)=-0.440 V and E_(Fe^(3+)//Fe^(2+))^(@)=0.770 V , then E_(Fe^(3+)//Fe)^(@) is -

If E_(Fe^(2+)|Fe)^0=-0.44V,E_((Fe^3+)||Fe^(2+))^0=0.77 . Calculate E_(Fe^(3+)|Fe)^0

GRB PUBLICATION-ELECTROCHEMISTY-Latimer Diagram, concentration cells
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